Question

prove that...
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(sec theta - tan theta) = 1/ (sec theta + tan theta)
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plzz give step by step explanation ✌️✌️

Answer 1

Answer:

Step-by-step explanation:

We know that  

• 1 + tan²A = sec² A

   ⇒ 1 = sec² A - tan² A

  ⇒ 1 = (sec A + tan A ) ( sec A - tan A)

∴   sec A + tan A = 1/(sec A - tan A ).