Question

please give me the answer of this question​

Answer 1

360° Answer

EXPLANATION:- BEACAUSE THE SUM OF ALL EXTERIOR ANGELS IS ALWAYS EQUALS TI 360°

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Answer 2

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SIMPLE METHOD:-

The sum of exterior angles of a triangle is 360°.

PROOF:-

BY ANGLE SUM PROPERTY OF A TRIANGLE WE HAVE

$\pink{ \bold{ \large{ \longrightarrow \: \angle 1 + \angle2 + \angle3 = 180 \degree}}}$

WE KNOW THAT THE SUM OF A LINEAR PAIR IS 180°

$\pink{ \bold{ \large{ \longrightarrow \: \angle 1 + \angle \: y = 180 \degree}}}$

$\pink{ \bold{ \large{ \longrightarrow \: \angle2 + \angle \: z= 180 \degree}}}$

$\pink{ \bold{ \large{ \longrightarrow \: \angle3 + \angle \: x= 180 \degree}}}$

HENCE THE VALUE OF x, y and z is

$\pink{ \bold{ \large{ \longrightarrow \: \angle \: x= 180 \degree - \angle3}}}$

$\pink{ \bold{ \large{ \longrightarrow \: \angle \: y = 180 \degree - \angle 1}}}$

$\pink{ \bold{ \large{ \longrightarrow \: \angle \: z= 180 \degree - \angle2}}}$

ADDING x, y and z we get

$\pink{ \bold{ \large{ \longrightarrow \: \angle \: x + \angle \: y + \angle \: z= 180 \degree - \angle3 + 180 \degree - \angle1 + 180 \degree - \angle2}}}$

Rearranging them we get

$\pink{ \bold{ \large{ \longrightarrow \: \angle \: x + \angle \: y + \angle \: z= 180 \degree + 180 \degree + 180 \degree - \angle1 - \angle2 - \angle3}}}$

TAKING NEGATIVE SIGN COMMON FROM <1, <2 and <3 we get:-

$\pink{ \bold{ \large{ \longrightarrow \: \angle \: x + \angle \: y + \angle \: z= 180 \degree + 180 \degree + 180 \degree - (\angle1 + \angle2 + \angle3)}}}$

PUTTING THE VALUE OF <1 + <2 + <3 WE GET

$\pink{ \bold{ \large{ \longrightarrow \: \angle \: x + \angle \: y + \angle \: z= 180 \degree + 180 \degree + 180 \degree - (180 \degree)}}}$

SOLVING THIS WE GET

$\pink{ \bold{ \large{ \longrightarrow \: \angle \: x + \angle \: y + \angle \: z= 540 \degree - 180 \degree}}}$

AND THE ANSWER IS

$\pink{ \bold{ \huge{ \Longrightarrow \: \angle \: x + \angle \: y + \angle \: z= 360 \degree}}}$