Question

please give me the answer of this question

Answer 1

I hope my answer is right.

Answer 2

Given that one of its zero is -2.

= > x = -2.

= > x + 2 = 0.

Now,

x + 2) x^3 - x^2 - 4x + 4( x^2 - 3x + 2

         x^3 + 2x^2

         --------------------------

                -3x^2 - 4x + 4

                -3x^2 - 6x

         ------------------------------

                              2x + 4

                              2x + 4

          --------------------------------

                                         0

       

Now,

= > x^2 - 3x + 2 = 0

= > x^2 - x - 2x + 2 = 0

= > x(x - 1) - 2(x - 1) = 0

= > (x - 2)(x - 1) = 0

= > x = 2,1.

Therefore, the zeroes are 1,2,-2.

Hope this helps!