Please give me the answer of this question with explanation..
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Answer:
Step-by-step explanation:
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Answer:
Step-by-step explanation:
a = (3 + √5)/2
1/a =[ 1/(3+√5)/2]
1/a = 2/(3+√5)
Rationalising we get
2/(3+√5) ×[ (3-√5)/(3-√5)]
= (6 - 2√5)/[(3)^2 - (√5)^2]
=(6-2√5/(9 - 5)
=(6 - 2√5)/4 = 6/4 - 2√5/4= 3/2 - √5/2
1/a = (3 - √5)/2
Now a^2 + 1/a^2 = (a + 1/a)^2 - 2 [ using identity (a+b)^2 and cancelling the 2ab term
= [ (3 + √5)/2 + (3 - √5)/2 ]^2 - 2
= [ (3 + √5 + 3 - √5 )/2 ]^2 - 2
= 6^2 - 2
= 36 -2
= 34 ( Ans)
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