Question

please give me the answer of this question with solution. please ​

Answer 1

Answer:

The leap year has 366 Days

And 2 Days are more than 52 weeks..

So

A = EVENT OF GETTING 53 FRIDAYS IN LEAP YEAR

m =2 (2 days are more)

n = 7( THERE ARE SEVEN DAYS IN WEEK)

SO P(A) =

$\frac{m}{n} = \frac{2}{7}$

So probability of 53 FRIDAYS in leap year is

$\frac{2}{7}$

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