Math, asked by moromi2529, 1 month ago

please give me the answer please...​

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Answers

Answered by Anonymous
83

\large\sf\underline{Questions\::}

1) What should be added to \sf\:6\frac{3}{4} to get 9 ?

2) What should be subtracted from 10 to get \sf\:3\frac{3}{4} ?

\large\sf\underline{Solutions\::}

Concepts to be used :

In order to solve the questions we need to frame an equation for both following the question. Then solving the equation we would get our required answers. So let's do !

1) Assuming x to be the required number.

Now according to the question :

\sf\:x~+6\frac{3}{4}=9

\sf\implies\:x~+\frac{27}{4}=9

  • LCM of 1 and 4 = 4

\sf\implies\:\frac{4x+27}{4}=9

  • Cross multiplying

\sf\implies\:4x+27=9 \times 4

\sf\implies\:4x+27=36

  • Transposing +27 to RHS it becomes -27

\sf\implies\:4x=36-27

\sf\implies\:4x=9

  • Transposing 4 to RHS it goes to the denominator

\small{\underline{\boxed{\mathrm\red{\implies\:x=\frac{9}{4}}}}}

Verifying :

In order to be sure that 9/4 is the required value we need to plug this value in the equation we had framed earlier. Doing so if we get LHS = RHS our answer would be correct.

Equation : \sf\:x~+6\frac{3}{4}=9

  • Substituting the value of x

\sf\longmapsto\:\frac{9}{4}~+6\frac{3}{4}=9

\sf\longmapsto\:\frac{9}{4}~+\frac{27}{4}=9

\sf\longmapsto\:\frac{9+27}{4}=9

\sf\longmapsto\:\frac{36}{4}=9

\sf\longmapsto\:\cancel{\frac{36}{4}}=9

\sf\longmapsto\:9=9

\bf\longmapsto\:LHS=RHS

\small\fbox\blue{Hence~Verified~!! }

======================

2) Assuming x to be the required number.

Now according to the question :

\sf\:x~-10=3\frac{3}{4}

\sf\implies\:x~-10=\frac{15}{4}

  • Cross multiplying

\sf\implies\:4(x-10)=15

\sf\implies\:4x-40=15

  • Transposing -40 to RHS it becomes +40

\sf\implies\:4x=15+40

\sf\implies\:4x=55

  • Transposing 4 to RHS it goes to the denominator

\small{\underline{\boxed{\mathrm\red{\implies\:x=\frac{55}{4}}}}}

Verifying :

In order to be sure that 55/4 is the required value we need to plug this value in the equation we had framed earlier. Doing so if we get LHS = RHS our answer would be correct.

Equation : \sf\:x~-10=3\frac{3}{4}

  • Substituting the value of x

\sf\longmapsto\:\frac{55}{4}~-10=3\frac{3}{4}

\sf\longmapsto\:\frac{55}{4}~-10=\frac{15}{4}

\sf\longmapsto\:\frac{55-40}{4}~=\frac{15}{4}

\sf\longmapsto\:\frac{15}{4}~=\frac{15}{4}

\bf\longmapsto\:LHS=RHS

\small\fbox\blue{Hence~Verified~!! }

======================

Required anSwers :

  • \sf\:\frac{9}{4} should be added.

  • \sf\:\frac{55}{4} should be subtracted .

!! Hope it helps !!

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