Question

Please give me the answer... Urgent hai bhai..

Answer 1

tan = p/ b
hypo^2 = m^2 - n^ 2 + n ^2
hypo = m
sin = p/ h = (√ m ^ 2 - n ^2) /m
cos = b/h = n/m

Answer 2

Answer:

tan = p/ b

hypo^2 = m^2 - n^ 2 + n ^2

hypo = m

sin = p/ h = (√ m ^ 2 - n ^2) /m

cos = b/h = n/m