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Answers
Answer:
(a) Energy required to break one bond of DNA is {10-20 J}/{1.6 x 10-19 J/eV} ≅ 0.06 eV
(b) Kinetic energy of an air molecule is {10-21 J}/{1.6 x 10-19 J/eV} ≅ 0.0062 eV
(c) The average human consumption in a day is {107 J}/{4.2 x 103 J/cal} ≅ 2400 kcal
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Answer:
(a) Energy required to break one bond
of DNA is
20
19
10 J ~ 0.06 eV
1.6 10 J/eV
−
− ×
where the symbol ‘~’ stands for approximate.
Note 0.1 eV = 100 meV (100 millielectron volt).
(b) The kinetic energy of an air molecule is
21
19
10 J ~ 0.0062 eV
1.6 10 J/eV
−
− ×
This is the same as 6.2 meV.
(c) The average human consumption in a day is
7
3
10 J ~ 2400 kcal
4.2×10 J/kcal
Explanation:
We point out a common misconception created
by newspapers and magazines. They mention
food values in calories and urge us to restrict
diet intake to below 2400 calories. What they
should be saying is kilocalories (kcal) and not
calories. A person consuming 2400 calories a
day will soon starve to death! 1 food calorie is
1 kcal.
gm baby take care