Question

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Answer 1

Step-by-step explanation:

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Answer 2

Hey Friend..

Here is the Solutions..

1. 5 + 4√3 - 2 + 3√3

= 5 - 2 + 4√3 + 3√3

= 3 + 7√3

is an irrational number.

2. Example of two irrational number = (2 + √2) and (5 + √2)

there sum = 7 + 2√2     which is irrational.

3. $6^n = (2 x 3)^n \\2^n x 3^n$

By putting any value of n, any power of 2 and 3 never ends with zero. Therefore there is no possible value of n, such that $6^n$ ends with zero.

4. √5 = 2.2360....

√10 = 3.162277....

A terminating decimal no. between 2.2360... and 3.162277...

= 2.5 i.e (5/2)

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I Hope This Will Help You...