Question

please give me the full solution​

Answer 1

Step-by-step explanation:

angle A + angleB= 360-160=200

if angle a =angle b

angle a=100

p is bisector

angle angle PAB =50 =PBA

angle APB=180-100=80 ans

Answer 2

Answer:

Hello ! guys here's Ur ans...

Given:

AP and BP bisects < A and <B respectively.

< C = 100° , < D = 60°.

Find:

< APB ..

Solution:

As, it's a quadrilateral..

So, < C + < B = 180° ( interior angles).

= 100 + < B = 180

= < B = 180-100=80.

And, as BP bisects < B , So < PBA = 80/2=40..

Similarly, <A + < D = 180

< A + 60 = 180

= < A = 180-60=120.

< PAB = 120/2=60.

Now, in ∆ APB ;

60+40+< APB = 180

= 100+<APB = 180

= < APB = 180-100=80°(ans)..

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