please give me the long division steps to get the square root of 171
Divyankasc:
Its not a perfect square but
Answers
Answered by
8
Plz refer to the image..
Steps ---
Step 1: Place a bar over every pair of digits starting from the unit digit. If the number of digits in it is odd, then the left-most single digit too will have a bar.Thus we have, 171.So 1st bar is on 71 and 2nd bar is on 1.
Step 2 : Find the largest number whose square is less than or equal to the 1st number,here it is '1'.
Step 3: Bring down the number under the next bar (i.e., 71 in this case) to the right of the remainder.
Step 4 : Add the divisor 1 and quotient 1 that gives us 2.
Step 5 : Think of a largest number in fill in the blank in such a way that the product of a new divisor and this digit is equal to or less than 71(new dividend). In this case 23 ×3 = 69.
Step 6 : Continue the same pattern (Add zeros as required)
Step 1: Place a bar over every pair of digits starting from the unit digit. If the number of digits in it is odd, then the left-most single digit too will have a bar.Thus we have, 171.So 1st bar is on 71 and 2nd bar is on 1.
Step 2 : Find the largest number whose square is less than or equal to the 1st number,here it is '1'.
Step 3: Bring down the number under the next bar (i.e., 71 in this case) to the right of the remainder.
Step 4 : Add the divisor 1 and quotient 1 that gives us 2.
Step 5 : Think of a largest number in fill in the blank in such a way that the product of a new divisor and this digit is equal to or less than 71(new dividend). In this case 23 ×3 = 69.
Step 6 : Continue the same pattern (Add zeros as required)
Attachments:
Answered by
6
13.076 ...
1 3 . 0 7 6
============
1 | 1 7 1 . 0 0 0 0
| 1
|======
23 | 7 1
| 6 9
|======
260 | 2 0 0
0
| ==========
2607 | 2 00 0 0
1 82 4 9
=========
26, 146 | 1 7 5, 1 0 0
1 5 6 8 7 6
===============
1 3 . 0 7 6
============
1 | 1 7 1 . 0 0 0 0
| 1
|======
23 | 7 1
| 6 9
|======
260 | 2 0 0
0
| ==========
2607 | 2 00 0 0
1 82 4 9
=========
26, 146 | 1 7 5, 1 0 0
1 5 6 8 7 6
===============
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