please give me the proof
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AIM : TO PROVE CE Bisects <ACB.
Which means { <ACE ~ <ECB }
⚫️By intersecting parallel lines
we know that
⚫️<ACE ~ <CDB (AAA_property) or (scaled model) Equation 1
And
⚫️<ECB ~ <CBD ( Alternate interior angles)
Equation 2
⚫️Now consider ^BCD which is a isosceles triangle containing CB = CD.
⚫️we know that, on an isosceles triangle angles subtend by equal sides are equal.
⚫️=> <CBD ~ <CDB. ----> Equation3
⚫️=> From Equations 1, 2 and 3 we can conclude that.
⚫️< ACE ~ <CDB ~ <CBD ~ <ECB
⚫️=>> <ACE. ~ <ECB
Hope it helps, if you have any doubts feel free to comment below :)))
Dersana:
thankuouuuit helped a lot..
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