Question

please give me the solution of question number 17 and get brainliest

Answer 1

Answer:

p(x) = 9x^2 - 28x + 3

Step-by-step explanation:

Alpha = A

Beta = B

A + B = -b/a = 4/3

A*B = c/a = 1/3

When zeros are A^2/B and B^2/A -

p(x) = x^2 - (A^2/B + B^2/A)x + (A^2/B * B^2/A)

p(x) = x^2 - (A^3 + B^3/AB)x + (AB)

the second term -

(A+B)(A^2 - AB + B^2) / AB

(A+B)( (A+b)^2 - 3AB) / AB

(4/3)( (4/3)^2 - 3*1/3) / 1/3

(4/3)( 16/9 - 1) * 3

4(7/9) = 28/9

the third term -

AB = 1/3

Therefore,

p(x) = x^2 - 28/9x + 1/3

p(x) = 9x^2 - 28x + 3

(If it's wrong, please do tell me)