Please give me the solution of the 6th question
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6 raise to power n cannot end with the digit 0 because in its prime factors are of the form 2×3 raise to power n and for a digit to end with 0 its prime factors should be of the form 2 raised to power x and 5 raise to power y (where x and y are natural numbers). So it doesn't end with a digit 0.
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