Question

please give the answer​

Answer 1

Answer

1) 0

Step-by-step explanation:

Objective approach :

put a = b = c = 1

then,  x/2 = 3

x = 6

Putting corresponding values in expression,

(2 - 2)^3 + (2 - 2)^3 + (2 - 2)^3-3(2 - 2)(2 - 2)(2 - 2)

=0

Subjective approach :

If you'll look closely, you will notice that expression is in the form of a³+b³+c³-3abc

and we know that,

a³+b³+c³-3abc=1/2 [a+b+c] {[a-b]²+[b-c]²+[c-a]²}

here,

a= x/3 -2a

b=x/3 - 2b

c=x/3 - 2c

so, a+b+c = (x/3+x/3+x/3) - 2(a+b+c)= x-x = 0

So the expression = 0 (as a+b+c term comes out to be zero)