Math, asked by daljeetnial, 4 months ago

please give the answer fast.......​

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Answered by nightread
3

Answer:

Given,

Diameter of wire = 3 mm

= \frac{3}{10} cm

Hence, one round of wire covers 3/10 cm of the height of the cylinder.

Length of cylinder = 12 cm

Wire will cover entire length of cylinder hence, number of rounds are:

Rounds \frac{3}{10} cm is covered in = 1 round

Rounds 1 cm is covered in = 1 × \frac{10}{3} rounds

Rounds 12 cm is covered in = 12 × \frac{10}{3} rounds

= 40 rounds

Length of wire required to complete one round = Circumference of cylinder

= 2πr

= 2π (\frac{10}{2})

= 10π cm

Length of wire required to cover whole cylinder = 10π × 40

= 400π cm

= 400 × 3.14

= 1256 cm

Density of copper = 8.88 g/cm³

Diameter of wire = \frac{3}{10} cm

Radius of wire = \frac{3}{10} × \frac{1}{2} cm

= \frac{3}{20} cm

Volume of wire = πr² × length

= π (\frac{3}{20})^{2} × 1256

= \frac{pi*9*1256}{400}

= \frac{35494.56}{400}

= 88.73 cm³

Density of wire = \frac{Mass}{Volume}

So, Mass = Density × Volume

= 8.88 × 88.73

= 787.83 gm

Length of wire = 1256 cm

Mass of wire = 788 gm

Hope it helps

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