Question

please give the answer of this question

Answer 1

HELLO DEAR,

[ (a + 1/b)^m × (a - 1/b)^n ] / [ (b + 1/a)^m × (b - 1/a)^n = (a/b)^(m + n)


⇒[ {(ba + 1)/b}^m × { (ba - 1)/b}^n ] / [ { (ab + 1)/a}^m × {ab - 1)/a }^n


⇒ [ { (ba + 1)^m .( ba - 1)^n } / )b^m . b^n ) ] × [ {(ba + )1^m . (ba - 1)^n } / (a^m .b^n ]

⇒[ (ba + 1)^m . (ba - 1)^n × (a^m × a ^ n) ] / [ (ba + 1)^m . (ba - 1)^n × (a^m × b^n ) ]

⇒(a^m . a^n) / (b^m . b^n)

⇒a^(m + n) / b^( m + n)

⇒(a / b) ^ ( m + n)


I HOPE ITS HELP YOU DEAR,
THANKS