Question

please give the correct answer​

Answer 1

Answer:

Area of \Delta ABC=\frac{1}{2}\times b\times h=\frac{1}{2}\times22\times3=33cm^2ΔABC=

2

1

×b×h=

2

1

×22×3=33cm

2

Area\ of\ \Delta ADC=\frac{1}{2}\times22\times3=33cm^2Area of ΔADC=

2

1

×22×3=33cm

2

Area of the quadrilateral ABCD

= Area of \Delta ABCΔABC+Area of \Delta ADCΔADC

=33cm^2+33cm^2=66cm^2=33cm

2

+33cm

2

=66cm

2

Hence, the required area= 66cm^266cm

2

Answer 2

$\huge\pink{\mid{\fbox{\underline{\underline{Answer}}}}\mid}$

1) Parallelogram or Rectangle

$\bf{2) \:l × b} \\\\ \bf {= 7×8} \\\\ \bf {= 56}$

$\bf{3) \: 2(l+b)} \\\\ \bf{= 2×(7+8)} \\\\ \bf{= 14+16} \\\\ \bf{= 30}$

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