Physics, asked by pushparakesh75235, 7 hours ago

please give this answer correctly ​

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Answered by Anonymous
35

Given :-

  • R1 = R2 = R3 = 30Ω

  • Voltage, v = 2 v

To find :-

  • Value of I, current in the circuit

Solution :-

In the given figure, we can see that resistors R1 and R2 are in series connection.

Their equivalent resistance will be:

 :  \implies \sf {R_{(s)} =R1 +R2  }

{ :  \implies \sf {R_{(s)}  = 30 \Omega   + 30\Omega}}

{ :  \implies \sf {R_{(s)}  = 60 \Omega   }}

Now this equivalent connection of R1 and R2 is in parallel connection with R3.

{ : \implies\sf\dfrac{1}{R_{(equivalent)}}=\dfrac{1}{R_{(s)}}+\dfrac{1}{R_3}}

{  : \implies \sf\dfrac{1}{R_{(equivalent)}}=\dfrac{1}{60\Omega}+\dfrac{1}{30\Omega}}

{  :  \implies\sf\dfrac{1}{R_{(equivalent)}}=\dfrac{1 + 2}{60\Omega}}

 {  : \implies\sf\dfrac{1}{R_{(equivalent)}}=\dfrac{3}{60\Omega}}

{  :  \implies\sf\dfrac{1}{R_{(equivalent)}}= \cancel\dfrac{3}{60\Omega}}

{ \implies \sf\dfrac{1}{R_{(equivalent)}}=\dfrac{1}{20\Omega}}

 \sf  : \implies R_{(equivalent)}=20\Omega

So the equivalent resistance of whole circuit is 20Ω.

Now applying ohm's law :-

\leadsto\sf  V = IR

Substitute values

\sf \leadsto 2v = I(20\Omega)

 \sf \leadsto  \dfrac{ 2v} {20\Omega} =I

 \sf \leadsto  \cancel \dfrac {2v} {20\Omega} =I

 \sf \leadsto  \dfrac {1v} {10\Omega} =I

 \sf \leadsto 0.1 \:  Ampere = I

So the current I flowing through the circuit is 0.1 Ampere.

[Omega will change into Ω when viewed from website]

Extra :-

  • Resistors in series : Resistors are said to be in series connection when more than 1 resistors are connected from end to end.

  • To find resistance in series connection, we apply formula , R = R1 + R2 + R3 . . .

  • Resistors in parallel : Resistors are said to be in a parallel connection when the end points of two or more resistors are connected to a same point.

  • To find resistance in parallel connection, we apply formula 1/R = 1/R1 + 1/R2 + 1/R3 . . .

  • Current : Remains same in series connection of resistors.

  • Voltage : Remains same in parallel connection of resistors.
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