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I also have This question in my textbook...
STEPS OF CONSTRUCTION :-
1} Draw segment QR of length 4.2cm.
2} Draw ray QS such that < RQS = 40°.
3} Mark point S such that length(QS) = 8.5cm.
4} Join points R and S.
5} Draw perpendicular bisector of segment RS intersecting ray QS and name the point of intersection as P.
6} Join P and R.
7} ∆PQR is the required triangle.
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Plzz mark it as brainliest...
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