Math, asked by raj5797, 1 year ago

Please guys give me answer

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Answered by siddhartharao77
6

Answer:

I = 3600

Step-by-step explanation:

Given, P = 5000,T= 4 years, I = 1200.

We know that I = P * R * T

1200 = 5000 * R * 4

1200 = R * 20000

R = 1200/20000

R = 0.06.


Given P = 15000, T = 4 years, R = 0.06.

We know that I = PRT

=> I = 15000 * 0.06 * 4

=> I = 3600.


Therefore, Interest = 3600.


Hope it helps!



raj5797: Hi brother
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Answered by BrainlyPromoter
3
Information provided to us:

Principal, P = ₹ 5000
Time, T = 4 years
Interest, I = ₹ 1200

We know that simple interest is equal to the product of principal, rate and time divided by 100.

Hence,
I = ( P * R * T ) / 100
=> 1200 = ( 5000 * R * 4 ) / 100
=> 1200 = 200R
=> R = 1200 / 200
=> R = 12 / 2 = 6 %

Therefore,

Rate of interest = 6 % p.a.

Now,

Principal, P2 = ₹ 15000
Rate, R = 6 % p.a.
Time, T = 4 years

Again,
I = ( P2 * R * T ) / 100
I = ( 15000 * 6 * 4 ) / 100
I = 150 * 24
I = ₹ 3600

Hence,

The required interest = ₹ 3600
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