Question

please guys I really need your help with this one. Given that P(x)=ax² +bx +1, P(1) =6, and P(-1)=2, determine the values of a and b​

Answer 1

P(x) = ax^2 + bx + c

P(0)= a(0) + b(0) + c = 1

=> c=1

P(1) = a(1 *1) + b(1) + 1 = 6

=> a+b=5 ——— A

P(-1)= a(-1 * -1) + b(-1) + 1 =2

=> a-b = 1 ——— B

Adding A and B

A + B = ( a + b) + ( a - b) = 5 + 1

=> 2*a = 6,

=> a = 3

Substitute a in A, 3 +b = 5, => b = 2

So, a = 3, b = 2, c=1

Answer 2

Step-by-step explanation:

please find attachment: