please guys I really need your help with this one. Given that P(x)=ax² +bx +1, P(1) =6, and P(-1)=2, determine the values of a and b
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P(x) = ax^2 + bx + c
P(0)= a(0) + b(0) + c = 1
=> c=1
P(1) = a(1 *1) + b(1) + 1 = 6
=> a+b=5 ——— A
P(-1)= a(-1 * -1) + b(-1) + 1 =2
=> a-b = 1 ——— B
Adding A and B
A + B = ( a + b) + ( a - b) = 5 + 1
=> 2*a = 6,
=> a = 3
Substitute a in A, 3 +b = 5, => b = 2
So, a = 3, b = 2, c=1
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