Math, asked by pineapplecompan, 1 year ago

please guys please help me please give the answer of question no. 12 (i) and (ii)

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Answered by Pranothi1

$i )[(x^{a-b} )^{ \frac{1}{ab} }][( x^{b-c} )^{ \frac{1}{bc} }][( x^{c-a}) ^{ \frac{1}{ac} } ] = [x^{(a-b) \frac{1}{ab} } ][ x^{(b-c) \frac{1}{bc} } ][ x^{(c-a) \frac{1}{ac}}] = x^{ \frac{a-b}{ab} } x^{ \frac{b-c}{bc} } x^{ \frac{c-a}{ca} } =1 $ $i )[(x^{a-b} )^{ \frac{1}{ab} }][( x^{b-c} )^{ \frac{1}{bc} }][( x^{c-a}) ^{ \frac{1}{ac} } ] = [x^{(a-b) \frac{1}{ab} } ][ x^{(b-c) \frac{1}{bc} } ][ x^{(c-a) \frac{1}{ac}}] = x^{ \frac{a-b}{ab} } x^{ \frac{b-c}{bc} } x^{ \frac{c-a}{ca} } =1 $

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Pranothi1: I could only type the first one

Pranothi1: but I wrote bothe of them

Pranothi1: if u have any doubts...pls don't hesitate to asj

Pranothi1: i mean ask

pineapplecompan: I will mark it brainliest

pineapplecompan: I understood. thanks for the help

Pranothi1: Thanks man

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