Please guys solve this question..
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Explanation:
in graph a= constant slope= constant velocity=
so, no acceleration and no force(in x axis)
in graph b= varying slope=varying velocity
so, acceleration and force is present(y axis)
using formula, s= it+1/2at²
initial velocity=0
so, ut=0
now, s= 1/2at²
4=1/2a(2)²
a=2m/s²
force= m.a
= 0.5kg×2
1N
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