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tan + sec -(sec2 -tan2) ÷tan - sec +1
tan + sec -{(sec-tan)(sec+tan)}÷tan-sec+1
sec+tan{1-(sec-tan)}÷tan-sec+1
sec+tan(1-sec+tan)÷tan-sec+1
so,1-sec+tan AND tan-sec+1 will get cancelled
Therefore, sec+tan=1÷cos+sin÷cos
1+sin÷cos
tan + sec -{(sec-tan)(sec+tan)}÷tan-sec+1
sec+tan{1-(sec-tan)}÷tan-sec+1
sec+tan(1-sec+tan)÷tan-sec+1
so,1-sec+tan AND tan-sec+1 will get cancelled
Therefore, sec+tan=1÷cos+sin÷cos
1+sin÷cos
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