Question

Please help..! A car of mass 1000kg starts from rest and comes down an inclined slope. If it travels a distance of 300 m in 30 sec , calculate (a) acceleration and (b) force acting on the bus?

Answer 1

ɢɪᴠᴇɴ :-

• Mass (m) = 1000kg
• Initial velocity (u) = 0 m/s --(At rest)
• Distance travelled (s) = 300 m
• Time taken (t) = 30 seconds

ᴛᴏ ғɪɴᴅ :-

• Acceleration (a)
• Force (F)

sᴏʟᴜᴛɪᴏɴ :-

On using 2nd equation of motion, we get,

➥ s = ut + ½ at²

➭ 300 = 0 × 30 + 1/2 × a × (30)²

➭ 300 = 1/2 × a × 900

➭ 300 = 900a/2

➭ 300 = 450a

➭ a = 300/450

➭ a = 0.6m/s²

Hence,

• Acceleration is 0.6m/s²

Now,

We know that,

➥ Force (F) = Mass(m) × Acceleration(a)

➭ F = m × a

➭ F = 1000 × 0.6

➭ F = 600 N

Hence,

• Force acting on car is 600 N