Question

PLEASE HELP
A polynomial f and one zero of f are given. Find the other zeros of f
$f(x)=x^3+2x^2-20x+24;-6$
$f(x)=2x^3+3x^2-39x-20;4$
$f(x)=x^3-3x^2-45x+175;-7$

Answer 1

F(x)=x^3+2x^2-20x+24

Here, if we put p(x)=2then

(2)^3+2×(2)^2-20(2)+24

On simplifying

We get,

= (8)+(2×4)-(40)+(24)

=8+8-40+24

=16-40+24

I.e=40-40

=0ans.