Question

please help and tell the correct answer. if it will be correct i will will follow and will give 10 thanks also and of course brainlest​

Answer 1

Answer:

SO,FIRST WE WILL FIND LENGTH AND BREADTH

LENGTH =33

BREADTH =7

SO,PERIMETER =2×(L+B)

=2×(33+7)

=2×40=80CM

AND DON'T FORGET THE SEMI CIRCLES

AS,THERE ARE 2 SEMI CIRCLES

SO WE CAN CALCULATE IT AS A CIRCLE

RADIUS=7÷2=3.5CM

CIRCUMFERENCE=π×r

= 22/7×3.5

ANSWER GET IN POINTS AND AT MANY NUMBERS AFTER POINT

SO,WE TAKE IT AS 11 CM

AREA=(A.OF RECTANGLE +A.OFCIRCLE)

=(33×7)+(22/7×3.5×3.5)

=231+22

=253CM²..

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Answer 2

Garden can be divided into one rectangle and 2semicircles.

Now, radius of semicircle,r=diameter/2 =7/2=3.5cm

length of rectangle =40-r-r

=40-3.5-3.5=40-(3.5+3.5)

=40-7=33m

breadth of rectangle =7m

area of semicircle =1/2πr^2

As r=3.5

area=1/2*22/7*7/2*7/2

=11*1/2*7/2

=77/4

area of rectangle =length *breadth

(l=33m,b=7m)

so, 33*7=231m^2

Area of garden=2*area of semicircle +area of rectangle

=2*77/4+231

=77/2+231

=38.5+231

=269.5m^2

(circumference of semicircle =1/2*2πr=1/2*2*22/7*7/2=11m)

Perimeter of garden=2*circumference of semicircle +2*length of rectangle

i. e, =2*11+2*33

=22+2*33

=24+33=792m