Math, asked by NITESH761, 9 hours ago

please help anybody who can​

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Answers

Answered by ripinpeace
111

 \rm{  \bf 49th  \: floor}

Step-by-step explanation:

Given -

Roger

  • Initial position = 32nd floor
  • Speed = 34 floors/min

Edward

  • Initial position = 98th floors
  • Speed = 98 floors/min

To find -

  • The floor on which Roger and Edward will meet.

Solution -

Let their paths cross after 't' minutes.

Distance covered by Roger in t minutes = 34t

Distance covered by Edward in t minutes = 98t

 \longmapsto \rm{ \bf \: 32 + 34t = 98 - 98t}

 \longmapsto \rm{ \bf \: 34t + 98t = 98 - 32}

\longmapsto \rm{ \bf \: 132t = 66}

\longmapsto \rm{ \bf \:t =  \dfrac{ \cancel{66} \:  \:  ^{1} }{ \cancel{132}   \:  \: ^{2} } }

\longmapsto \rm{ \bf \overline{ \underline  \pink{  \boxed{ \bf\:t =  \dfrac{1}{2} }}}}

Hence, number of floors covered by Roger in 1/2 mins = 34 × 1/2 = 17.

∴ their paths cross at (32 + 17)th i.e. 49th floor.

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