Question

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A stone is allowed to fall from the top of a tower 100 M high and at the same time another stone is projected vertically upwards from the ground with a velocity of 25 m per second. Calculate when and where the two stones will meet.


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Answer 1

i hope u can understand

Answer 2

Hey Dear...
First of All Nice Question :D

And Here is Your Answer ☺️...
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Let "t" = time after which both stones meet

"S" = distance travelled by the stone dropped from the top of tower

(100-S) = distance travelled by the projected stone.

◆ i) For stone dropped from the top of tower-S = 0 + 1/2 (-10) t²or, S = 5t²

◆ ii) For stone projected upward(100 - S) = 25t + 1/2 (-10) t²= 25t - 5t²

Adding i) and ii) , We get 100 = 25t
or t = 4 s

Therefore, Two stones will meet after 4 s.

◆ ¡¡¡) Put value of t = 4 s in Equation i) , we get S = 5 × 16 = 80 m.

Thus , both the stone will meet at a distance of 80 m from the top of tower.

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Hope it Helped You Out :D
Thanks... :)

@batradivjyot25