Question

Please Help.
Factorise....

Answer 1

Answer:

Step-by-step explanation:

a^12 - b^12

USE FORMULA::

a^2 - b^2 = ( a+b) ( a-b)

(a^6 + b^6) ( a^6 - b^6)

( a^6 + b^6) ( a^3 + b^3) ( a^3 - b^3)

USE FORMULAS::

a^3 + b^3 = ( a+b) ( a^2 -ab + b^2)

AND,,

a^3 - b^3 = ( a-b) ( a^2 + ab + b^2)

(a^2 + b^2) ( a^4 -a^2b^2 + b^4) ( a+ b) (a^2 -ab+b^2) ( a-b) (a^2 +ab + b^2)

Plzz mark it brillant

Answer 2

$\underline{\red{\bold{QUESTION}}}$ ➡

$\bold{Factorise \: : a {}^{12} - b {}^{12} }$

$\underline{\red{\bold{SOLUTION}}}$ ➡

$\bold{a {}^{12} - b {}^{12} } \\ \\ \bold{ = (a {}^{6} ) {}^{2} - ( b {}^{6} ) {}^{2} } \\ \\ \bold{ = (a {}^{6} + b {}^{6} )(a {}^{6} - b {}^{6} )} \\ \\ \bold{ = (a {}^{6} + b {}^{6})[( a {}^{3}) {}^{2} - (b {}^{3} ) {}^{2}]} \\ \\ \bold{ = (a {}^{6} + b {}^{6} )[(a {}^{3} + b {}^{3})( a {}^{3} - b {}^{3}) ]} \\ \\ \bold{ =( a {}^{6} + b {}^{6})( a {}^{3} + b {}^{3})( a - b)(a {}^{2} + ab + b {}^{2} } \\ \\ \bold{ = (a - b)(a {}^{2} + ab + b {}^{2} )(a {}^{3} + b {}^{3})( a {}^{6} + b {}^{6} )} \\ \\ \bold{=(a-b)(a{}^{2}+ab+b{}^{2})(a+b)(a{}^{2}-ab+b{}^{2})(a{}^{6}+b{}^{6})}$

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$\bold{ \red{ \mathfrak{THANKS...}}}$