Question

~please help find it~

Find area and boundry​

Answer 1

Step-by-step explanation:

${r}^{2} = {10}^{2} - {8}^{2} \\ \\ r = \sqrt{100 - 64} \\ \\ = \sqrt{36} \\ \\ = 6 \: cm \\ \\ area \: of \: semi \: circle = \pi {r}^{2} \div 2 \\ \\ = \pi(36) \div 2 \\ \\ = 18\pi \: sq \: cm. \\ \\ area \: of \: triangle = \frac{1}{2} \times (6 + 6) \times 8 \\ \\ = 4 \times 12 \\ \\ = 48 \: sq \: cm. \\ \\ total \: area = 18\pi + 48 \: \: \: sq \: cms.$

$length \: of \: boundary = \pi \times r + 10 + 10 \\ \\ = \pi \times 6 + 20 \\ \\ 20 + 6\pi \: cms.$