Question

PLEASE HELP FOR BRAINLIEST! :)

Answer 1

6. As we know,

Tn =a+(n-1)d

=4+(100-1)5

= 4+495

T100 = 499

where a is 1st term

d is common difference

and n is no. of terms

Answer 2

Answer:

Ans 5 -) (a)

Ans 6 :-) (b)

Step-by-step explanation:

Ans 5 :-)

as here there is a sequence being followed

i.e. 5x - 2 = y

 

for--e::::5e - 2 = 18

                 5e = 18+2

                 5e = 20

                   e = 20÷5

                   e = 4

and hence only one option is having 'e' as 4.

Ans 6 :-)

a=4

d=5

$a_{n}=a+(n-1)d$

$a_{100}=a+(100-1)d\\a_{100}=4+(99)5\\a_{100}=4+495\\a_{100}=499$

and hence only one option is having $100^{th}$ term as 499.