Question

please help for this question ​

Answer 1

Answer:

Let numerator be x and denominator be y.

So, the fraction will be x/y.

According to the question

$\frac{x - 2}{y + 3} = \frac{1}{4}$

$cross \: multiply$

$4(x - 2) = 1(y + 3)$

$4x - 8 = y + 3$

$4x - y - 8 - 3 = 0$

$4x - y - 11 = 0$

If x=1 If x=2

4(1)-y-11=0 4(2)-y-11=0

4-y-11=0 8-y-11=0

(-y)-11+4=0 (-y)-11+8=0

(-y)-7=0 (-y)-3=0

(-y)=7 (-y) =3

y=(-7) y=(-3)

The two solution for the equation is (1,-7) and (2,-3).

I'm not sure about the solution for the equation.