Question

please help guys ..
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Answer 1

(i)

$\boxed{\sf{(2x^2 - 5y) (5x + 2y^2) ; [x = 2, y = -1]}}$

Applying the values of "x" and "y" to the equation:

$\sf{\implies [(2\times(2)^2)-(5\times (-1))]\times[(5\times 2)+ (2\times(-1)^2)] }$

$\sf{\implies [(2\times4)-(5\times -1)]\times[(5\times 2)+(2\times -1)] }$

$\sf{\implies [8-(-5)]\times[10+(-2)] }$

$\sf{\implies [8+5]\times[10-2] }$

$\sf{\implies 13\times8 }$

$\sf{\implies 104 }$

Answer = 104

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(ii)

$\boxed{\sf{(-\dfrac{1}{4}a+\dfrac{1}{5}b)(\dfrac{1}{4}a+\dfrac{1}{5}b};[a=8, b=5]}$

Applying the values of "a" and "b" to the equation:

$\sf{\implies [(-\dfrac{1}{4}\times8)+(\dfrac{1}{5}\times 5)]\times[(\dfrac{1}{4}\times 8)+(\dfrac{1}{5}\times 5)]}$

$\sf{\implies [(-\dfrac{8}{4})+(\dfrac{5}{5})]\times[(\dfrac{8}{4})+(\dfrac{5}{5})]}$

$\sf{\implies [-2+1]\times[2+1]}$

$\sf{\implies -1\times 3}$

$\sf{\implies -3}$

Answer = -3

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(iii)

$\boxed{\sf{(m+n)(2m-3n); [m=-2, n=0]}}$

Applying the values of "m" and "n" to the equation:

$\sf{\implies (-2+0)\times [(2\times -2)-(3\times 0)]}$

$\sf{\implies (-2+0)\times (-4-0)}$

$\sf{\implies -2\times-4}$

$\sf{\implies -8}$

Answer = -8

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(iv)

$\boxed{\sf{(0.1p+0.2q)(0.2m-0.1p); [p=10, q=5]}}$

Applying the values of "p" and "q" to the equation:

$\sf{\implies [(0.1\times 10)+(0.2\times 5)]\times[(0.2\times 5)-(0.1\times 10)]}$

$\sf{\implies [1+1]\times[1-1]}$

$\sf{\implies 2\times0}$

$\sf{\implies 0}$

Answer = 0

Answer 2

Answer:

104,-3,-8,0

Step-by-step explanation:

104,-3,-8,0