Please help guys!!
please solve step by step..
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Answered by
2
HI ANSHU!
WE CANT HAVE ANY VALUE OF SIN2016 & COSEC2016. IF YOU WANT ANSWER THEN IT IS 1.
BECAUSE SIN THETA+ COSEC THETA=1.
♥♥THANKS♥♥
WE CANT HAVE ANY VALUE OF SIN2016 & COSEC2016. IF YOU WANT ANSWER THEN IT IS 1.
BECAUSE SIN THETA+ COSEC THETA=1.
♥♥THANKS♥♥
Anonymous:
but answer is 2
Answered by
5
Heya
_______________________________
Sin0 + 1/Sin0 = 2
=>
Sin²0 - 2Sin0 + 1 = 0
let Sin0 = z
=>
z² -2z + 1 = 0
=>
( z - 1)² = 0
=>
( z - 1 ) = 0
=>
z = 1
So, Sin0 = 1
Sin0 = Sin90
0 = 90
So, Sin^2016 0 + Cosec^2016 0 =
{ Sin0 } ^2016 + (Cosec0)^2016
= { 1}^2016 + { 1/1 }^2016
= 1 + 1 = 2
in given question it must be given that
90° ≤ 0≤0°
_______________________________
Sin0 + 1/Sin0 = 2
=>
Sin²0 - 2Sin0 + 1 = 0
let Sin0 = z
=>
z² -2z + 1 = 0
=>
( z - 1)² = 0
=>
( z - 1 ) = 0
=>
z = 1
So, Sin0 = 1
Sin0 = Sin90
0 = 90
So, Sin^2016 0 + Cosec^2016 0 =
{ Sin0 } ^2016 + (Cosec0)^2016
= { 1}^2016 + { 1/1 }^2016
= 1 + 1 = 2
in given question it must be given that
90° ≤ 0≤0°
bhai boy hu !!
ok bro
hmm
y such said status?
*sad
hmm !! h koye baat h bhai !!
May you get back ur love.
no !!;
hehe..xD
yeah..may !!
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