Math, asked by ppp45, 1 year ago

please help i will mark as braillest​

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Answered by Aditya1510
0

Answer:

1

Step-by-step explanation:

(x)^(p-q)(p+q)*(x)^(q-r)(q+r)*(x)^(r-p)(r+p)

=(x)^p^2-q^2 * (x)^q^2-r^2 * (x)^r^2-p^2

=(x)^p^2 - q^2 + q^2 - r^2 + r^2 - p^2

=(x)^0

=1

I hope this will help you...

PLEASE MARK ME AS THE BRAINLIEST..

Answered by Anonymous
0

Answer:

=> 1

Step-by-step explanation:

=> (x^p/x^q)^p+q × (x^q/x^r)^q+r × (x^r/x^p)^r+p

=> (x^p-q)^p+q + (x^q-r)^q+r × (x^r-p)^r+p

=> x^(p-q)(p+q) × x^(q-r)(q+r) × x^(r-p)(r+p)

=> 1

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