Question

the acceleration due to gravity on the surface of the moon is 1.7 m/s^2 . What is the time period of a simple pendulum on the moon , if its time period on the earth is 3.5seconds​

Answer 1

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Let T1 and T2 are the time periods of the pendulums on the earth and moon respectively.Similarly if corresponding accelerations due to gravity are g1 and g2 then for a simple pendulum of length l, we have

T1=2π√(l/g1) and

T2=2π√(l/g2)

This gives

T1/T2=√(g2/g1)

Or

T2=T1√(g1/g2)

Putting the values of different quantities we get time period on moon as

T2=3.5√(9.8/1.7)

=8.4 s