please help...im in a hurry..
the point which devide the line segment joining the point (5,4) and(-6,-7) in the ratio 1:3 lies in the ....dash...quadrant.
class 10th chapter -cordinate geometry
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In which quadrant does the point which divides the line segment joining the points(5,4) and (-6,-7) in the ratio 1:3 internally lie?
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1 Answer

Guilherme Mastrange
, studied at CEFET-RJ
Answered November 20, 2017
You can do this by the length (size) of each axis.
Lets do it first for x axis: the delta is 5–(-6), wich is 11. So the line extends 11 units in the x axis, starting in -6 and ending at 5.
We have to divide the interval in 4 segments, so we can have 1 part to the left and 3 parts to the right, and vice-versa.
But, if you mean 1 part from 3 total parts, you have to divide for 3.
Lets suppose we divide for 4 to fit the ratio, we find that each part has the length of 2,75…, in the interval from -6 to 5. Lets sum:
1° point (from -6 to 5): -6+2,75 = -3,25
2°point (from 5 to -6): 5–2,75 = 2,25
Doing the same procedure to y axis, we have:
1°point (from -7 to 4): -7+2,75 = -4,25
2°point (from 4 to -7): 4–2,75 = 1,25
Finally we have the points coordinates:
1° point: from left to right (-3,25;-4,25) third quadrant
2°point: from right to left (2,25;1,25) first quadrant