Physics, asked by chiragdt123, 11 months ago

Please Help In Doing This Problem​

Attachments:

Answers

Answered by ashish781
1

Answer:

I. 6×10^-2

ii. 6cm³

iii. 50/6×1000=8333kg/m³

Explanation:

I. if solid body weighted in air =m.g=50. 10^-3N

if body weighted in water = 44×10^-3N

the change in weight is upthrust because it opposes ,

upthrust=6×10^-3

ii. upthrust is carried out by water replaced by solid body.

replaced water mass=6g

: 1g--------------1ml or 1cm³

: 6g--------------6ml or 6cm³

iii. relative density

= mass of solid/volume escaped

mass of escaped water/volume escaped

=mass of solid

mass of escaped water

=50/6×1000

=8333kg/m³

Similar questions