Question

please help
In the circuit shown in figure, a current I drawn from 60 V battery until switch is opened. Current flow in circuit after the switch closed is​

Answer 1

Answer: option 1=

Explanation: Read the language of the question. *Until* the switch is opened is equivalent to the switch is closed. So if I current is drawn *until* the switch is opened, it means I current is drawn when switch is closed.

Answer 2

Answer:

Option 3

Explaination:

(a) When a switch is open then the circuit is open hence the current through the circuit is zero.

(b) when the switch is closed than circuit is closed than the current through V=IR

And I=V/R  

This is called the Ohm's law

Under the assumption that all physical parameters and temperatures remain constant, Ohm's law asserts that the voltage across a conductor is directly proportional to the current flowing through it.

Now we can see that

3Ω and 3Ω are in series so the net resistance is 6Ω

Which is in parallel in with 3Ω and 6Ω

So:

$\frac{1}{3}+\frac{1}{6} +\frac{1}{6}=\frac{4}{6}=\frac{2}{3}$

And this value is in series with 6Ω

So we have

$\frac{2}{3}+6=\frac{20}{3\\}$

Now I=V/R

$\frac{3}{2}I$

Hence proven

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