Question

please help in this question​

Answer 1

Explanation:

Given:Circuit diagram

To find:

1) Total resistance

2) Current

3) Potential difference across R1

Solution:

1) Total resistance:

Resistance R2 and R3 are in parallel arrangement.

Equivalent resistance of this arrangement is

$\frac{1}{R_{eq}}=\frac{1}{R_2}+\frac{1}{R_3}\\\\\frac{1}{R_{eq}}=\frac{1}{8}+\frac{1}{12}\\\\\frac{1}{R_{eq}}=\frac{1(3)+1(2)}{24}\\\\\frac{1}{R_{eq}}=\frac{5}{24}\\\\R_{eq}=\frac{24}{5}$

$R_{eq}$ and $R_1$are in series

Thus

$R_T=R_{eq}+R_1\\\\R_T=\frac{24}{5}+7.2\\\\R_T=4.8+7.2\\\\R_T=12\:ohm$

Therefore,

Total resistance of the circuit is 12 ohm.

2) Total current passing in the circuit:

We know that from Ohm's law

$V=IR\\\\I=\frac{V}{R}\\\\I=\frac{6}{12}\\\\I=0.5\:Ampere$

3) Potential difference across R1

$V_1=IR_1\\\\V_1=0.5\times7.2\\\\V_1=3.6\:V$

Final answer:

1) Total resistance of the circuit is 12 ohm.

2) Total current passing in the circuit is 0.5 Ampere.

3) Potential difference across R1 is 3.6 V.

Hope it helps you.

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