please help it's urgent
Answers
x+1=0
x=−1
8×1+4+5=17
Sometimes referred to as the incompressibility, the bulk modulus is a measure of the ability of a substance to withstand changes in volume when under compression on all sides. ... It is equal to the quotient of the applied pressure divided by the relative deformation.Given:
A wooden block of mass 400 gram float vertically in a liquid of density 0.8 gram/cm cube. The volume of the block is 625 cm³.
To find:
Volume of block above liquid surface ?
Calculation:
In case of floating, the weight of the block is being balanced by the buoyant force:
\therefore \: F_{b} = mg∴F
b
=mg
\implies \: (V_{inside}) \rho g = (V_{total}) \sigma g⟹(V
inside
)ρg=(V
total
)σg
\implies \: \dfrac{V_{inside}}{V_{total}} = \dfrac{ \sigma}{ \rho}⟹
V
total
V
inside
=
ρ
σ
\implies \: \dfrac{V_{inside}}{625} = \dfrac{ (\frac{400}{625} )}{ 0.8}⟹
625
V
inside
=
0.8
(
625
400
)
\implies \: \dfrac{V_{inside}}{625} = \dfrac{ 0.64}{ 0.8}⟹
625
V
inside
=
0.8
0.64
\implies \: \dfrac{V_{inside}}{625} = 0.8⟹
625
V
inside
=0.8
\implies \: V_{inside} = 500 \: {cm}^{3}⟹V
inside
=500cm
3
\implies \: V_{outside} =(625 - 500 )\: {cm}^{3}⟹V
outside
=(625−500)cm
3
\implies \: V_{outside} =125 \: {cm}^{3}⟹V
outside
=125cm
3