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If 7th term of a ap is equal to 11/7 times of 11 term. find 18th term.
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Answer:
I have given two solution of your question in two methods.
Step-by-step explanation:
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Answer:
A(18)=0
Step-by-step explanation:
Given:
A(7)=11/7 times of A(11)
A(18)=?
let the 7th term be (a+6d)
let the 11th term be (a+10d)
NOW, ATQ:
7(a+6d)=11(a+10d)
7a+42d=11a+110d
7a-11a=110d-42d
-4a= 68d
-a= 17d -------(I)
Now,
A(18)=(a+17d) {from eq (I)}
A(18)=a+(-a)
A(18)=0
hence, the A(18) is 0.
hope it helps :)
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