Please!! help... its easy....
The difference of the ages of 2 sisters was 5 years.Ten years ago,the sum of their ages was 65 years.What was their present ages??
Answers
Answered by
1
Let the present age of first sister be x and
Let the present age of second sister be y.
Now , A.T.Q
x - y = 5
x = 5 + y ---------------------------------------------(1)
Ten years ago
( x - 10 ) + ( y - 10 ) = 65----------------------(2)
Putting the value of (1) in (2)
5 + y - 10 + y - 10 = 65
2y -15 = 65
2y = 65 + 15
y= 80/2
y= 40 years.
And for x , putting the value of x in (1 )
x = 5 + 40
x= 45
Hence the ages of two sisters are 45 years and 40 years.
Let the present age of second sister be y.
Now , A.T.Q
x - y = 5
x = 5 + y ---------------------------------------------(1)
Ten years ago
( x - 10 ) + ( y - 10 ) = 65----------------------(2)
Putting the value of (1) in (2)
5 + y - 10 + y - 10 = 65
2y -15 = 65
2y = 65 + 15
y= 80/2
y= 40 years.
And for x , putting the value of x in (1 )
x = 5 + 40
x= 45
Hence the ages of two sisters are 45 years and 40 years.
shivam2000:
mark my answer best plzzzzzzzzzzzzzzzzzzz
Similar questions