Math, asked by apmhteam, 1 year ago

Please!! help... its easy....
The difference of the ages of 2 sisters was 5 years.Ten years ago,the sum of their ages was 65 years.What was their present ages??

Answers

Answered by shivam2000
1
Let the present age of first sister be x and 
Let the present age of second sister be y.

Now , A.T.Q
x - y = 5
x = 5 + y ---------------------------------------------(1)

Ten years ago 
( x - 10 ) + ( y - 10 ) = 65----------------------(2)
Putting the value of (1) in (2)
5 + y - 10 + y - 10 = 65
2y -15  = 65
2y = 65 + 15
y= 80/2
y= 40 years.

And for x , putting the value of x in (1 ) 
x = 5 + 40
x= 45

Hence the ages of two sisters are 45 years and 40 years.
  

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