Question

please help me...........
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Answer 1

Answer:

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Answer 2

$\huge\star{\tt{\underline{\underline{\red{Answer}}}}}\star$

Given Graph is of a Velocity-Time Graph

we know that the area enclosed by the graph is the distance travelled by the body

So we need to Find the Area of Graph

Area of Graph= ∆ ABE + Rect BCFE + ∆ CFD

(SEE THE ATTACHMENT FOR REFERENCE)

Area of ∆ ABE

= ½ x AE x BE

= ½ x 4 x 50

= $\bold{\boxed{100m{}^{2}}}$

Area of Rect BCFE

= FE x BE

= (6-4) x 50

= $\bold{\boxed{100m{}^{2}}}$

Area of ∆CFD

= ½ x FD x CF

= ½ x (10-6) x 50

= ½ x 4 x 50

=$\bold{\boxed{100m{}^{2}}}$

Area of Graph = 100 + 100 + 100

$\implies$ = $\large{\boxed{\boxed{300m{}^{2}}}}$