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Yes , the sequence obtained is an AP because the difference between every term is equal .
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Yes , it is an AP
Step-by-step explanation:
f(n) = 3n -10
f(1) = -7
f(2) = -4
f(3) = -1
f(4) = 2
f(5) = 5
Obtained sequence is -7 , -4 , -1 , 2 , 5
d = -4 -(-7) = -4 +7 = 3
d = -1 -(-4) = -1 + 4 = 3
d = 2 -(-1) = 2 +1 = 3
d = 5 - 2 = 3
The common difference is same for all the terms , hence it is an AP
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