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one trigonometric identity
cos A cos B − sin A sin B = cos ( A+B )
cos (π\4-x) cos (π\4-y)-sin (π\4-x) sin (π\4-y)
Here A = (π\4-x), B= (π\4-y)
= cos [(π\4-x) +(π\4-y)]
= cos [ (π\4+π\4)-(x+y)]
= cos [ (π\2) - (x+y)]
= sin ( x+y )
Since
cos (π\2-x) = sin (x).
Plz mark as the brainliest .
cos A cos B − sin A sin B = cos ( A+B )
cos (π\4-x) cos (π\4-y)-sin (π\4-x) sin (π\4-y)
Here A = (π\4-x), B= (π\4-y)
= cos [(π\4-x) +(π\4-y)]
= cos [ (π\4+π\4)-(x+y)]
= cos [ (π\2) - (x+y)]
= sin ( x+y )
Since
cos (π\2-x) = sin (x).
Plz mark as the brainliest .
FIREBIRD:
ty sis
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