PLEASE HELP ME!!!
A)FIND THE DISTANCE BETWEEN 10 AND 30.
B)WHAT IS THE NEGATIVE ACCELERATION OF THE BODY.
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Answer:
distance = area under the V-T curve
in this case the rect
area=length×breadth
=20×20(from the graph)
=400 metre
now,acceleration is equal to the slope of the V-T graph
OR
V=U+AT
V=0 ; U=20 ;T=10
O=20+A×10
10A=-20
acceleration = -20/10
= -2m/sec2
hope it helps
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