Question

please help me as soon as

Answer 1

maybe...
at the poles.

Answer 2

Equator is answer to your question
Explanation =We know that the value of acceleration due to gravity ,g is deduced to be:

 by the Law of Gravitational attraction.

According to this, the value of, g depends on the mass and the radius of the Earth (G being a constant).

However, as we know that the Earth is not perfectly spherical but bulged out (R is slightly more at the equator) at the equator on account of its rotation.

Thus, it is found that the value of g is 0.5% more at the poles than it is at the equator.

As a result the weight (W=mg) of the same amount of sugar must also be greater at thepoles. 

Weight of 1kg sugar at equator measured by the weighing machine=1X9.8=9.8N

Mass measured (as per the calibrated weighing machine) will be= (9.8/9,8)=1kg

Weight of 1kg sugar at poles=1X 9.85=9.85N

Mass measured (as per the calibrated weighing machine) will be= (9.85/9,8)=1.005kg

So at the poles, even 1kg sugar will be read as 1.005 kg by the vendor and you will get lesser sugar by him.

Thus, it is profitable to buy sugar at the equator than on poles.